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【SAT真题】2013年7月9日-17日SAT官方每日一题数学篇

2013-07-18 09:38:19 来源: Collegeboard 责编：楷维留学指南

【SAT真题】2013年7月9、12、15日SAT官方每日一题数学选择题，分享给广大SAT考生。

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　　【2013年7月9日SAT考试官方每日一题答案及解析】

正确答案:D

解析:

Both a minus b = 6 and b minus 3 = 6 . The equation cannot be solved for because there are two unknowns. The value of can be found by solving the equation for . It follows that must equal . The value of can now be substituted into the equation , giving a minus 9 = 6 . Therefore, must equal .

　　【2013年7月12日SAT考试官方每日一题答案及解析】

正确答案:E

解析:

Triangle A B C is isosceles, and the measure of angle is 74 degrees . Let the measure of angle be b degrees , and let the measure of angle be c degrees . The sum of the measures of the angles of a triangle is 180 degrees , so 74 plus b plus c equals 180 . An isosceles triangle has two angles of equal measure, so b equals 74 , or c equals 74 , or b equals c does not equal 74 .

If , then , so , and the measures of the angles of the triangle are , and .
If , then , so , and the measures of the angles of the triangle are , and .
If , then , so , and . In this case, the measures of the angles of the triangle are , and .

Hence if the measure of angle is 74 degrees , the possible measures of angles and , respectively, are and 32 degrees ; and ; and 53 degrees and . Therefore, it is not possible to determine what must be the measure of another angle of this triangle.

　　【2013年7月15日SAT考试官方每日一题答案及解析】

正确答案:C

解析:

The outcome space for this experiment is the set of all ordered pairs (a comma b) where represents the first number that comes up, and represents the second one. Since and can take all the values through , there will be a total of possible outcomes. The outcomes can be represented in a table as shown:

2013年7月15日SAT考试官方每日一题答案及解析

Among all the pairs (a comma b) , are pairs for which a = b . So remaining pairs will have a not equal to b . Notice that the number of pairs for which a less than b is the same with the number of pairs

(a comma b) for which a greater than b . Therefore the number of pairs

(a comma b) for which a less than b , is (half of ). Then the probability that is equal to (number of pairs (a comma b) comma where a less than b) over (number of all possible outcomes) = 15 over 36 = 5 over 12